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Download /( /cos 40^{/circ} /cos 80^{/circ} /cos 160^{/circ} /cos 240^{/circ}= /) (a) /( 1 / 2 /) (b) 1 (... MP3 & MP4 You can download the song /( /cos 40^{/circ} /cos 80^{/circ} /cos 160^{/circ} /cos 240^{/circ}= /) (a) /( 1 / 2 /) (b) 1 (... for free at MetroLagu. To see details of the /( /cos 40^{/circ} /cos 80^{/circ} /cos 160^{/circ} /cos 240^{/circ}= /) (a) /( 1 / 2 /) (b) 1 (... song, click on the appropriate title, then the download link for /( /cos 40^{/circ} /cos 80^{/circ} /cos 160^{/circ} /cos 240^{/circ}= /) (a) /( 1 / 2 /) (b) 1 (... is on the next page.

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\( \cos 40^{\circ}+\cos 80^{\circ}+\cos 160^{\circ}+\cos 240^{\circ}= \) (A) 1 (B) \( 1 / 2 \) (...
(PW Solutions)  View
\( \cos 40^{\circ}+\cos 80^{\circ}+\cos 160^{\circ}+\cos 240^{\circ}= \) (A) \( 1 / 2 \) (B) 1 (...
(PW Solutions)  View
सिद्ध कीजिए कि- \[ \cos 40^{\circ} \cos 80^{\circ} \cos 160^{\circ}=-\frac{1}{8} \]
(PW Solutions)  View
Prove that: cos40 . cos100 . cos160 = 1/8
(Solution With X)  View
The value of \( \cos 52^{\circ}+\cos 68^{\circ}+\cos 172^{\circ} \) is (A) 1 (B) 2 (C) \( 3 / 2 ...
(PW Solutions)  View
The value of `sec 40^(@)+sec 80^(@)+sec 160^(@)` will be
(Doubtnut)  View
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(lets derive)  View
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